Read 3 floating-point numbers. After, print the roots of bhaskara’s formula. If it's impossible to calculate the roots because a division by zero or a square root of a negative number, presents the message “Impossivel calcular”.
Input
Read 3 floating-point numbers A, B and C.
Output
Print the result with 5 digits after the decimal point or the message if it is impossible to calculate.
Read 4 integer values A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).
Input
Four integer numbers A, B, C and D.
Output
Show the corresponding message after the validation of the values.
Read a value of floating point with two decimal places. This represents a monetary value. After this, calculate the smallest possible number of notes and coins on which the value can be decomposed. The considered notes are of 100, 50, 20, 10, 5, 2. The possible coins are of 1, 0.50, 0.25, 0.10, 0.05 and 0.01. Print the message “NOTAS:” followed by the list of notes and the message “MOEDAS:” followed by the list of coins.
Input
The input file contains a value of floating point N (0 ≤ N ≤ 1000000.00).
Output
Print the minimum quantity of banknotes and coins necessary to change the initial value, as the given example.
Input Sample
Output Sample
576.73
NOTAS:
5 nota(s) de R$ 100.00
1 nota(s) de R$ 50.00
1 nota(s) de R$ 20.00
0 nota(s) de R$ 10.00
1 nota(s) de R$ 5.00
0 nota(s) de R$ 2.00
MOEDAS:
1 moeda(s) de R$ 1.00
1 moeda(s) de R$ 0.50
0 moeda(s) de R$ 0.25
2 moeda(s) de R$ 0.10
0 moeda(s) de R$ 0.05
3 moeda(s) de R$ 0.01
4.00
NOTAS:
0 nota(s) de R$ 100.00
0 nota(s) de R$ 50.00
0 nota(s) de R$ 20.00
0 nota(s) de R$ 10.00
0 nota(s) de R$ 5.00
2 nota(s) de R$ 2.00
MOEDAS:
0 moeda(s) de R$ 1.00
0 moeda(s) de R$ 0.50
0 moeda(s) de R$ 0.25
0 moeda(s) de R$ 0.10
0 moeda(s) de R$ 0.05
0 moeda(s) de R$ 0.01
91.01
NOTAS:
0 nota(s) de R$ 100.00
1 nota(s) de R$ 50.00
2 nota(s) de R$ 20.00
0 nota(s) de R$ 10.00
0 nota(s) de R$ 5.00
0 nota(s) de R$ 2.00
MOEDAS:
1 moeda(s) de R$ 1.00
0 moeda(s) de R$ 0.50
0 moeda(s) de R$ 0.25
0 moeda(s) de R$ 0.10
0 moeda(s) de R$ 0.05
1 moeda(s) de R$ 0.01
Details: The Best Bangla C Programming book ever. written by Tamim Shahriar Subeen and Published with Dimik Prokashoni. It has three sequence Part-1, Part-2 and Part-3. That is Part-1 and we are being ready to upload others part of this book very soon. Stay Connected.
Read an integer value corresponding to a person's age (in days) and print it in years, months and days, followed by its respective message “ano(s)”, “mes(es)”, “dia(s)”.
Note: only to facilitate the calculation, consider the whole year with 365 days and 30 days every month. In the cases of test there will never be a situation that allows 12 months and some days, like 360, 363 or 364. This is just an exercise for the purpose of testing simple mathematical reasoning.
In this problem you have to read an integer value and calculate the smallest possible number of banknotes in which the value may be decomposed. The possible banknotes are 100, 50, 20, 10, 5, 2 e 1. Print the read value and the list of banknotes.
Input
The input file contains an integer value N (0 < N < 1000000).
Output
Print the read number and the minimum quantity of each necessary banknotes in Portuguese language, as the given example. Do not forget to print the end of line after each line, otherwise you will receive “Presentation Error”.
Input Sample
Output Sample
576
576
5 nota(s) de R$ 100,00
1 nota(s) de R$ 50,00
1 nota(s) de R$ 20,00
0 nota(s) de R$ 10,00
1 nota(s) de R$ 5,00
0 nota(s) de R$ 2,00
1 nota(s) de R$ 1,00
11257
11257
112 nota(s) de R$ 100,00
1 nota(s) de R$ 50,00
0 nota(s) de R$ 20,00
0 nota(s) de R$ 10,00
1 nota(s) de R$ 5,00
1 nota(s) de R$ 2,00
0 nota(s) de R$ 1,00
503
503
5 nota(s) de R$ 100,00
0 nota(s) de R$ 50,00
0 nota(s) de R$ 20,00
0 nota(s) de R$ 10,00
0 nota(s) de R$ 5,00
1 nota(s) de R$ 2,00
1 nota(s) de R$ 1,00
Little John wants to calculate and show the amount of spent fuel liters on a trip, using a car that does 12 Km/L. For this, he would like you to help him through a simple program. To perform the calculation, you have to read spent time (in hours) and the same average speed (km/h). In this way, you can get distance and then, calculate how many liters would be needed. Show the value with three decimal places after the point.
Input
The input file contains two integers. The first one is the spent time in the trip (in hours). The second one is the average speed during the trip (in Km/h).
Output
Print how many liters would be needed to do this trip, with three digits after the decimal point.
Two cars (X and Y) leave in the same direction. The car X leaves with a constant speed of 60 km/h and the car Y leaves with a constant speed of 90 km / h.
In one hour (60 minutes) the car Y can get a distance of 30 kilometers from the X car, in other words, it can get away one kilometer for each 2 minutes.
Read the distance (in km) and calculate how long it takes (in minutes) for the car Y to take this distance in relation to the other car.
Input
The input file contains 1 integer value.
Output
Print the necessary time followed by the message "minutos" that means minutes in Portuguese.
Read the four values corresponding to the x and y axes of two points in the plane, p1 (x1, y1) and p2 (x2, y2) and calculate the distance between them, showing four decimal places after the comma, according to the formula:
Distance =
Input
The input file contains two lines of data. The first one contains two double values: x1 y1 and the second one also contains two double values with one digit after the decimal point: x2 y2.
Output
Calculate and print the distance value using the provided formula, with 4 digits after the decimal point.
Calculate a car's average consumption being provided the total distance traveled (in Km) and the spent fuel total (in liters).
Input
The input file contains two values: one integer value X representing the total distance (in Km) and the second one is a floating point number Y representing the spent fuel total, with a digit after the decimal point.
Output
Present a value that represents the average consumption of a car with 3 digits after the decimal point, followed by the message "km/l".
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Injamamul Haque Sonet Graphic Designer | Web Developer
Born in Narsingdi district. Studied in Panchkandi College, Monohardi and currently studying in the Department of Software Engineering at Daffodil International University.
A small attempt to share what I have learned everyday life.