URI 1040 : Average 3 Solve In C, C++, Java And Python Solution

Problem: URI Online Judge | 1038

URI Online Judge | 1040

Average 3

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read four numbers (N1, N2, N3, N4), which one with 1 digit after the decimal point, corresponding to 4 scores obtained by a student. Calculate the average with weights 2, 3, 4 e 1 respectively, for these 4 scores and print the message "Media: " (Average), followed by the calculated result. If the average was 7.0 or more, print the message "Aluno aprovado." (Approved Student). If the average was less than 5.0, print the message: "Aluno reprovado." (Reproved Student). If the average was between 5.0 and 6.9, including these, the program must print the message "Aluno em exame." (In exam student).

In case of exam, read one more score. Print the message "Nota do exame: " (Exam score) followed by the typed score. Recalculate the average (sum the exam score with the previous calculated average and divide by 2) and print the message “Aluno aprovado.” (Approved student) in case of average 5.0 or more) or "Aluno reprovado." (Reproved student) in case of average 4.9 or less. For these 2 cases (approved or reproved after the exam) print the message "Media final: " (Final average) followed by the final average for this student in the last line.

Input

The input contains four floating point numbers that represent the students' grades.

Output

Print all the answers with one digit after the decimal point.

Input Sample	Output Sample
2.0 4.0 7.5 8.0 6.4	Media: 5.4 Aluno em exame. Nota do exame: 6.4 Aluno aprovado. Media final: 5.9

2.0 6.5 4.0 9.0

Media: 4.8 Aluno reprovado.

9.0 4.0 8.5 9.0

Media: 7.3 Aluno aprovado.

Solution In C:

URI 1038 : Snack Solve In C, C++, Java And Python Solution

Problem: URI Online Judge | 1038

URI Online Judge | 1038

Snack

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Using the following table, write a program that reads a code and the amount of an item. After, print the value to pay. This is a very simple program with the only intention of practice of selection commands.

Input

The input file contains two integer numbers X and Y. X is the product code and Y is the quantity of this item according to the above table.

Output

The output must be a message "Total: R$ " followed by the total value to be paid, with 2 digits after the decimal point.

Input Sample	Output Sample
3 2	Total: R$ 10.00

4 3	Total: R$ 6.00

2 3	Total: R$ 13.50

Solution In C:

URI 1037 : Interval In C, C++, Java And Python

Problem: URI Online Judge | 1037

URI Online Judge | 1037

Interval

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

You must make a program that read a float-point number and print a message saying in which of following intervals the number belongs: [0,25] (25,50], (50,75], (75,100]. If the read number is less than zero or greather than 100, the program must print the message “Fora de intervalo” that means "Out of Interval".

The symbol '(' represents greather than. For example:
[0,25] indicates numbers between 0 and 25.0000, including both.
(25,50] indicates numbers greather than 25 (25.00001) up to 50.0000000.

Input

The input file contains a floating-point number.

Output

The output must be a message like following example.

Input Sample	Output Sample
25.01	Intervalo (25,50]

25.00

Intervalo [0,25]

100.00

Intervalo (75,100]

-25.02

Fora de intervalo

Solution In C:

URI 1036 : Bhaskara's Formula Solve In C, C++, Java And Python

Problem: URI Online Judge | 1036

URI Online Judge | 1036

Bhaskara's Formula

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read 3 floating-point numbers. After, print the roots of bhaskara’s formula. If it's impossible to calculate the roots because a division by zero or a square root of a negative number, presents the message “Impossivel calcular”.

Input

Read 3 floating-point numbers A, B and C.

Output

Print the result with 5 digits after the decimal point or the message if it is impossible to calculate.

Input Samples	Output Samples
10.0 20.1 5.1	R1 = -0.29788 R2 = -1.71212

0.0 20.0 5.0

Impossivel calcular

10.3 203.0 5.0

R1 = -0.02466 R2 = -19.68408

10.0 3.0 5.0

Impossivel calcular

Solution In C:

URI 1035 : Selection Test 1 Solve In C, C++, Java And Python

Problem: URI Online Judge | 1035

URI Online Judge | 1035

Selection Test 1

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read 4 integer values A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).

Input

Four integer numbers A, B, C and D.

Output

Show the corresponding message after the validation of the values​​.

Input Sample	Output Sample
5 6 7 8	Valores nao aceitos

2 3 2 6

Valores aceitos

Solution In C:

URI 1021 : Banknotes and Coins Solve In C, C++, Java And Python

Problem: URI Online Judge | 1021

URI Online Judge | 1021

Banknotes and Coins

By Neilor Tonin, URI  Brazil

Timelimit: 1

Read a value of floating point with two decimal places. This represents a monetary value. After this, calculate the smallest possible number of notes and coins on which the value can be decomposed. The considered notes are of 100, 50, 20, 10, 5, 2. The possible coins are of 1, 0.50, 0.25, 0.10, 0.05 and 0.01. Print the message “NOTAS:” followed by the list of notes and the message “MOEDAS:” followed by the list of coins.

Input

The input file contains a value of floating point N (0 ≤ N ≤ 1000000.00).

Output

Print the minimum quantity of banknotes and coins necessary to change the initial value, as the given example.

Input Sample	Output Sample
576.73	NOTAS: 5 nota(s) de R$ 100.00 1 nota(s) de R$ 50.00 1 nota(s) de R$ 20.00 0 nota(s) de R$ 10.00 1 nota(s) de R$ 5.00 0 nota(s) de R$ 2.00 MOEDAS: 1 moeda(s) de R$ 1.00 1 moeda(s) de R$ 0.50 0 moeda(s) de R$ 0.25 2 moeda(s) de R$ 0.10 0 moeda(s) de R$ 0.05 3 moeda(s) de R$ 0.01

4.00	NOTAS: 0 nota(s) de R$ 100.00 0 nota(s) de R$ 50.00 0 nota(s) de R$ 20.00 0 nota(s) de R$ 10.00 0 nota(s) de R$ 5.00 2 nota(s) de R$ 2.00 MOEDAS: 0 moeda(s) de R$ 1.00 0 moeda(s) de R$ 0.50 0 moeda(s) de R$ 0.25 0 moeda(s) de R$ 0.10 0 moeda(s) de R$ 0.05 0 moeda(s) de R$ 0.01

91.01

NOTAS: 0 nota(s) de R$ 100.00 1 nota(s) de R$ 50.00 2 nota(s) de R$ 20.00 0 nota(s) de R$ 10.00 0 nota(s) de R$ 5.00 0 nota(s) de R$ 2.00 MOEDAS: 1 moeda(s) de R$ 1.00 0 moeda(s) de R$ 0.50 0 moeda(s) de R$ 0.25 0 moeda(s) de R$ 0.10 0 moeda(s) de R$ 0.05 1 moeda(s) de R$ 0.01

Solution In C:

URI 1020 : Age in Days Solve In C, C++, Java And Python

Problem: URI Online Judge | 1020

Age in Days

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read an integer value corresponding to a person's age (in days) and print it in years, months and days, followed by its respective message “ano(s)”, “mes(es)”, “dia(s)”.

Note: only to facilitate the calculation, consider the whole year with 365 days and 30 days every month. In the cases of test there will never be a situation that allows 12 months and some days, like 360, 363 or 364. This is just an exercise for the purpose of testing simple mathematical reasoning.

Input

The input file contains 1 integer value.

Output

Print the output, like the following example.

Input Sample	Output Sample
400	1 ano(s) 1 mes(es) 5 dia(s)

800	2 ano(s) 2 mes(es) 10 dia(s)

30	0 ano(s) 1 mes(es) 0 dia(s)

Solution In C:

URI 1019 : Time Conversion Solve In C, C++, Java And Python

Problem: URI Online Judge | 1019

Time Conversion

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read an integer value, which is the duration in seconds of a certain event in a factory, and inform it expressed in hours:minutes:seconds.

Input

The input file contains an integer N.

Output

Print the read time in the input file (seconds) converted in hours:minutes:seconds like the following example.

Input Sample	Output Sample
556	0:9:16

1

0:0:1

140153

38:55:53

Solutions In C:

URI 1018 : Banknotes Solve In C, C++, Java And Python

Problem: URI Online Judge | 1018

Banknotes

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

In this problem you have to read an integer value and calculate the smallest possible number of banknotes in which the value may be decomposed. The possible banknotes are 100, 50, 20, 10, 5, 2 e 1. Print the read value and the list of banknotes.

Input

The input file contains an integer value N (0 < N < 1000000).

Output

Print the read number and the minimum quantity of each necessary banknotes in Portuguese language, as the given example. Do not forget to print the end of line after each line, otherwise you will receive “Presentation Error”.

Input Sample	Output Sample
576	576 5 nota(s) de R$ 100,00 1 nota(s) de R$ 50,00 1 nota(s) de R$ 20,00 0 nota(s) de R$ 10,00 1 nota(s) de R$ 5,00 0 nota(s) de R$ 2,00 1 nota(s) de R$ 1,00

11257

11257 112 nota(s) de R$ 100,00 1 nota(s) de R$ 50,00 0 nota(s) de R$ 20,00 0 nota(s) de R$ 10,00 1 nota(s) de R$ 5,00 1 nota(s) de R$ 2,00 0 nota(s) de R$ 1,00

503	503 5 nota(s) de R$ 100,00 0 nota(s) de R$ 50,00 0 nota(s) de R$ 20,00 0 nota(s) de R$ 10,00 0 nota(s) de R$ 5,00 1 nota(s) de R$ 2,00 1 nota(s) de R$ 1,00

Solution In C:

URI 1017 : Fuel Spent Solve In C, C++, Java And Python

Problem: URI Online Judge | 1017

Fuel Spent

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Little John wants to calculate and show the amount of spent fuel liters on a trip, using a car that does 12 Km/L. For this, he would like you to help him through a simple program. To perform the calculation, you have to read spent time (in hours) and the same average speed (km/h). In this way, you can get distance and then, calculate how many liters would be needed. Show the value with three decimal places after the point.

Input

The input file contains two integers. The first one is the spent time in the trip (in hours). The second one is the average speed during the trip (in Km/h).

Output

Print how many liters would be needed to do this trip, with three digits after the decimal point.

Input Sample	Output Sample
10 85	70.833

2 92

15.333

22 67

122.833

Solution In C:

URI 1016 : Distance Solve In C, C++, Java And Python

Problem: URI Online Judge | 1016

Distance

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Two cars (X and Y) leave in the same direction. The car X leaves with a constant speed of 60 km/h and the car Y leaves with a constant speed of 90 km / h.

In one hour (60 minutes) the car Y can get a distance of 30 kilometers from the X car, in other words, it can get away one kilometer for each 2 minutes.

Read the distance (in km) and calculate how long it takes (in minutes) for the car Y to take this distance in relation to the other car.

Input

The input file contains 1 integer value.

Output

Print the necessary time followed by the message "minutos" that means minutes in Portuguese.

Input Sample	Output Sample
30	60 minutos

110	220 minutos

7	14 minutos

Solution In C:

URI 1015 : Distance Between Two Points Solve In C, C++, Java And Python

Problem: URI Online Judge | 1015

Distance Between Two Points

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read the four values corresponding to the x and y axes of two points in the plane, p1 (x1, y1) and p2 (x2, y2) and calculate the distance between them, showing four decimal places after the comma, according to the formula:

Distance = 

Input

The input file contains two lines of data. The first one contains two double values: x1 y1 and the second one also contains two double values with one digit after the decimal point: x2 y2.

Output

Calculate and print the distance value using the provided formula, with 4 digits after the decimal point.

Input Sample	Output Sample
1.0 7.0 5.0 9.0	4.4721

-2.5 0.4 12.1 7.3

16.1484

2.5 -0.4 -12.2 7.0

16.4575

Solution In C:

URI 1014 : Consumption Solve In C, C++, Java And Python

Problem: URI Online Judge | 1014

Consumption

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Calculate a car's average consumption being provided the total distance traveled (in Km) and the spent fuel total (in liters).

Input

The input file contains two values: one integer value X representing the total distance (in Km) and the second one is a floating point number Y  representing the spent fuel total, with a digit after the decimal point.

Output

Present a value that represents the average consumption of a car with 3 digits after the decimal point, followed by the message "km/l".

Input Sample	Output Sample
500 35.0	14.286 km/l

2254 124.4

18.119 km/l

4554 464.6

9.802 km/l

Solution In C:

URI 1013 : The Greatest Solve In C, C++, Java And Python

Problem: URI Online Judge | 1013

The Greatest

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Make a program that reads 3 integer values and present the greatest one followed by the message "eh o maior". Use the following formula:

Input

The input file contains 3 integer values.

Output

Print the greatest of these three values followed by a space and the message “eh o maior”.

Input Samples	Output Samples
7 14 106	106 eh o maior

217 14 6

217 eh o maior

Solution In C:

URI 1012 : Area Solve In C, C++, Java And Python

Problem: URI Online Judge | 1012

Area

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Make a program that reads three floating point values: A, B and C. Then, calculate and show:
a) the area of the rectangled triangle that has base A and height C.
b) the area of the radius's circle C. (pi = 3.14159)
c) the area of the trapezium which has A and B by base, and C by height.
d) the area of ​​the square that has side B.
e) the area of the rectangle that has sides A and B.

Input

The input file contains three double values with one digit after the decimal point.

Output

The output file must contain 5 lines of data. Each line corresponds to one of the areas described above, always with a corresponding message (in Portuguese) and one space between the two points and the value. The value calculated must be presented with 3 digits after the decimal point.

Input Samples	Output Samples
3.0 4.0 5.2	TRIANGULO: 7.800 CIRCULO: 84.949 TRAPEZIO: 18.200 QUADRADO: 16.000 RETANGULO: 12.000

12.7 10.4 15.2

TRIANGULO: 96.520 CIRCULO: 725.833 TRAPEZIO´: 175.560 QUADRADO: 108.160 RETANGULO: 132.080

Solution In C:

URI 1011 : Sphere Solve In C, C++, Java And Python

Problem: URI Online Judge | 1011

Sphere

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Make a program that calculates and shows the volume of a sphere being provided the value of its radius (R) . The formula to calculate the volume is: (4/3) * pi * R3. Consider (assign) for pi the value 3.14159.

Tip: Use (4/3.0) or (4.0/3) in your formula, because some languages (including C++) assume that the division's result between two integers is another integer. :)

Input

The input contains a value of floating point (double precision).

Output

The output must be a message "VOLUME" like the following example with a space before and after the equal signal. The value must be presented with 3 digits after the decimal point.

Input Samples	Output Samples
3	VOLUME = 113.097

15	VOLUME = 14137.155

1523	VOLUME = 14797486501.627

Solution In C:

URI 1010 : Simple Calculate Solve In C, C++, Java And Python

Problem: URI Online Judge | 1010

Simple Calculate

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

In this problem, the task is to read a code of a product 1, the number of units of product 1, the price for one unit of product 1, the code of a product 2, the number of units of product 2 and the price for one unit of product 2. After this, calculate and show the amount to be paid.

Input

The input file contains two lines of data. In each line there will be 3 values: two integers and a floating value with 2 digits after the decimal point.

Output

The output file must be a message like the following example where "Valor a pagar" means Value to Pay. Remember the space after ":" and after "R$" symbol. The value must be presented with 2 digits after the point.

Input Samples	Output Samples
12 1 5.30 16 2 5.10	VALOR A PAGAR: R$ 15.50

13 2 15.30 161 4 5.20

VALOR A PAGAR: R$ 51.40

1 1 15.10 2 1 15.10

VALOR A PAGAR: R$ 30.20

Solution In C: